hi team, how can I define the dictionary in the parameters.yml? classes: - name: '98' weight: 1.0 - name: '900' weight: 4.0 - name: '1001' weight: 4.0 - name: '1200' weight: 1.0 - name: '1300' weight: 4.0 when I define like this, it seem like it is a list instead of dictionary when I call in params['classes']

Someone will reply to you shortly. In the meantime, this might help:

hi @Kai Lok! how does your

node(...)

look like in

pipeline.py

?

def load_class_weights(params: Dict[str, Any]) -> Dict[str, float]: classes = params['classes'] class_weights = {cls['name']: cls['weight'] for cls in classes} return class_weights

that's your node function, indeed

params.yml can oni be list ya?

how are you declaring the pipeline?

return pipeline(
  node(
    func=load_class_weights,
    inputs=[...]  # <-----?

from kedro.pipeline import Pipeline, pipeline, node from .nodes import load_class_weights def create_pipeline(**kwargs) -> Pipeline: return pipeline([ node( func=load_class_weights, inputs="params:classes", outputs=None, name="load_class_weights_node" ), ])

exactly. so, that's like doing

>>> load_class_weights(params=parameters["classes])

therefore you're receiving a list, you don't need

classes = params["classes"]

inside your function. does that make sense?

means I'm doing redundant work here by receiving a dict then convert back to dict? how can I check whether I'm defining it correctly or not before I send it back to the main function?

@Kai Lok

params.yml can oni be list ya?

It’s a

dict[str, Any]

. Meaning that top level keys are strings, and then values can be literals, lists, other dicts, etc.

thank you guys, I change it to received list instead. easier. 🙂